Let be a function satisfying with and be a function that satisfies then the value of the integral is
a)
b)
c)
d)
Your Answer
Evaluate dx, a>0
a) 2π
d) aπ
If dx =Ax + B ln sin(x
Then value of (A, B) is
a) (sinα, cosα)
b) (cosα, sinα)
c) (sinα, cosα)
d) (cosα, sinα)
=
a) ln + c
b) ln + c
c) ln + c
d) ln + c
If
then A is equal to
a) 0
Then the value of is
a) 2
If and then
If then is equal to
The value of the integral is
is
b) 0
Let If then
one of the possible values of k is
a) 15
b) 16
c) 63
d) 64
a) 20
b) 8
c) 10
d) 18
, then equals
b) 1
d) 0
dx is
Evaluate dx
c) 0
d) 1
d) None of the above
Let f(x) be differentiable for all x. If f (1) = − 2 and for x [1, 6] then
a) f(6)=5
b) f(6) < 5
c) f(6) < 8
d) f(6) ≥ 8
The value of the definite integral is
a) – 1
b) 2
The area bounded by the curve y = f(x), the X–axis and the ordinate x = 1 and x = b is (b – 1) sin (3b + 4). Then f(x) is
a) (x – 1) cos (3x + 4)
b) sin(3x + 4)
c) sin(3x + 4) + 3(x – 1) cos (3x + 4)
d) none of these
The slope of the tangent to the curve y = f(x) at [x, f(x)] is 2x + 1. The curve passes through (1, 2), then the area bounded by the curve and X–axis, and the line x = 1 is
d) 6
Let then the real roots of the equation
are
a) ± 1
d) 0 and 1
The area bounded by the curves
and the X–axis in the first quadrant is
a) 9
c) 36
The area enclosed between y = ax2 and x = ay2 (a > 0)
is one square unit. Then the value of a is
c) 1