Solve cosy ln(secx + tanx) dx = cosx ln(secy + tany) dy
My Self Assessment
a) lnc = –
Solve the differential equation
Solve xy (1 + y) dy = (1 – x2) (1 – y) dx
Solve
Find the function f which satisfies the equation
Solve (x + y) (dx – dy) = dx + dy
Solve (2x + y – 3) dy = (x + 2y – 3) dx
Solve (2x + y + 1) dx + (4x + 2y – 1) dy = 0
Solve (4x + 6y + 5) dy = (3y + 2x + 4) dx
Solve if y = 1 when x = 1
Solve y dx – x dy + lnx dx = 0
