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Question 346

Find the equations of the tangent and the normal to the following curve
4x3 – 3xy2 + 6x2 – 5xy – 8y2 + 9x + 14 = 0
at the point (− 2, 3)


a) Tangent is 9x + 2y + 12 = 0; Normal is 2x – 9y + 31 = 0

b) Tangent is 9x − 2y + 12 = 0; Normal is 2x + 9y + 31 = 0

c) Tangent is 2x + 9y + 12 = 0; normal is 9x – 2y + 31 = 0

d) Tangent is 2x − 9y + 12 = 0; Normal is 9x + 2y + 31 = 0

Your Answer

ABCD   CLEAR