|
776 |
If then the domain of f(x) is
If then the domain of f(x) is
|
IIT 1985 |
|
|
777 |
The real numbers x1, x2, x3 satisfying the equation x3 – x2 + βx + γ = 0 are in Arithmetic Progression. Find the interval in which β and γ lie.
The real numbers x1, x2, x3 satisfying the equation x3 – x2 + βx + γ = 0 are in Arithmetic Progression. Find the interval in which β and γ lie.
|
IIT 1996 |
|
|
778 |
Let p, q, r be three mutually perpendicular vectors of the same magnitude. If x satisfies the equation p ((x – q) p) + q ((x – r) q) + r ((x – p) r) = 0 then x is given by a)  b)  c)  d) 
|
IIT 1997 |
|
|
779 |
Let f(x) be a non constant differentiable function defined on (−∞, ∞) such that f(x) = f(1 – x) and then a) vanishes at twice an (0, 1) b)  c)  d) 
Let f(x) be a non constant differentiable function defined on (−∞, ∞) such that f(x) = f(1 – x) and then a) vanishes at twice an (0, 1) b)  c)  d) 
|
IIT 2008 |
|
|
780 |
Let and a unit vector c be coplanar. If c is perpendicular to a then c is equal to a)  b)  c)  d) 
Let and a unit vector c be coplanar. If c is perpendicular to a then c is equal to a)  b)  c)  d) 
|
IIT 1999 |
|
|
781 |
Number of solutions of lying in the interval is a) 0 b) 1 c) 2 d) 3
Number of solutions of lying in the interval is a) 0 b) 1 c) 2 d) 3
|
IIT 1993 |
|
|
782 |
If three complex numbers are in Arithmetic Progression, then they lie on a circle in a complex plane. a) True b) False
If three complex numbers are in Arithmetic Progression, then they lie on a circle in a complex plane. a) True b) False
|
IIT 1985 |
|
|
783 |
Multiple choice The vector is a) A unit vector b) Makes an angle with the vector  c) Parallel to vector  d) Perpendicular to the vector 
Multiple choice The vector is a) A unit vector b) Makes an angle with the vector  c) Parallel to vector  d) Perpendicular to the vector 
|
IIT 1994 |
|
|
784 |
A1, A2, …… , An are the vertices of a regular polygon with n sides and O is the centre. Show that
A1, A2, …… , An are the vertices of a regular polygon with n sides and O is the centre. Show that
|
IIT 1982 |
|
|
785 |
If A, B, C are such that |B| = |C|. Prove that 
If A, B, C are such that |B| = |C|. Prove that 
|
IIT 1997 |
|
|
786 |
Let u and v be unit vectors. If w is a vector such that , then prove that and that equality holds if and only if is perpendicular to 
|
IIT 1999 |
|
|
787 |
Let n be an odd integer. If sin nθ = for every value of θ, then a) = 1, = 3 b) = 0, = n c) = −1, = n d) = 1, = 
|
IIT 1998 |
|
|
788 |
If is the unit vector along the incident ray, is a unit vector along the reflected ray and is a unit vector along the outward drawn normal to the plane mirror at the point of incidence. Find in terms of and 
|
IIT 2005 |
|
|
789 |
True / False For any three vectors a, b and c a) True b) False
True / False For any three vectors a, b and c a) True b) False
|
IIT 1989 |
|
|
790 |
Multiple choices For a positive integer n, let . . . then a)  b)  c)  d) 
Multiple choices For a positive integer n, let . . . then a)  b)  c)  d) 
|
IIT 1999 |
|
|
791 |
For all ,  a) True b) False
For all ,  a) True b) False
|
IIT 1981 |
|
|
792 |
Let f (x) = |x – 1| then a) f (x2) = |f (x)|2 b) f (x + y) = f (x) + f (y) c) f ( ) = |f (x)| d) None of these
Let f (x) = |x – 1| then a) f (x2) = |f (x)|2 b) f (x + y) = f (x) + f (y) c) f ( ) = |f (x)| d) None of these
|
IIT 1983 |
|
|
793 |
Let the vectors represent the edges of a regular hexagon Statement 1 - because Statement 2 -  a) Statement 1 and 2 are true and Statement 2 is a correct explanation of statement 1. b) Statement 1 and 2 are true and Statement 2 is not a correct explanation of statement 1. c) Statement 1 is true. Statement 2 is false. d) Statement 1 is false. Statement 2 is true.
Let the vectors represent the edges of a regular hexagon Statement 1 - because Statement 2 -  a) Statement 1 and 2 are true and Statement 2 is a correct explanation of statement 1. b) Statement 1 and 2 are true and Statement 2 is not a correct explanation of statement 1. c) Statement 1 is true. Statement 2 is false. d) Statement 1 is false. Statement 2 is true.
|
IIT 2007 |
|
|
794 |
Find the smallest possible value of p for which the equation a)  b)  c)  d) 
Find the smallest possible value of p for which the equation a)  b)  c)  d) 
|
IIT 1995 |
|
|
795 |
If f (x) = for every real x then the minimum value of f a) does not exist because f is unbounded b) is not attained even though f is bounded c) is equal to 1 d) is equal to −1
If f (x) = for every real x then the minimum value of f a) does not exist because f is unbounded b) is not attained even though f is bounded c) is equal to 1 d) is equal to −1
|
IIT 1998 |
|
|
796 |
Find the larger of cos(lnθ) and ln(cosθ) if < θ < . a) cos(lnθ) b) ln(cosθ) c) Neither is larger throughout the interval
Find the larger of cos(lnθ) and ln(cosθ) if < θ < . a) cos(lnθ) b) ln(cosθ) c) Neither is larger throughout the interval
|
IIT 1983 |
|
|
797 |
If the function f : [ 1, ) → [ 1, ) is defined by f (x) = 2x(x – 1) then f -1(x) is a)  b) ( ) c) ( ) d) 
|
IIT 1999 |
|
|
798 |
If are in harmonic progression then ………… a) 1 b)  c)  d) 
If are in harmonic progression then ………… a) 1 b)  c)  d) 
|
IIT 1997 |
|
|
799 |
If  then x equals a)  b) 1 c)  d) –1
If  then x equals a)  b) 1 c)  d) –1
|
IIT 1999 |
|
|
800 |
Let f ( x ) = , x ≠ 1 then for what value of a is f ( f (x)) = x a)  b)  c) 1 d) 1
Let f ( x ) = , x ≠ 1 then for what value of a is f ( f (x)) = x a)  b)  c) 1 d) 1
|
IIT 2001 |
|