The lines 2x + 3y + 1 = 0 and 3x – y – 4 = 0 tie along diameter of a circle of circumference 10π. Then the equation of the circle is

a) x² + y² – 2x + 2y – 23 = 0

b) x² + y² – 2x – 2y – 23 = 0

c) x² + y² + 2x + 2y – 23 = 0

d) x² + y² + 2x – 2y – 23 = 0