Let E = (2n + 1) (2n + 3) (2n + 5).  .  . (4n – 3) (4n – 1); n > 1 then E is divisible by

a) ⁿC_n/2

b) ²ⁿC_n

c) ³ⁿC_n

d) ⁴ⁿC_2n