1301 |
If f is a continuous function with as |x| → ∞ then show that every line y = mx intersects the curve .
If f is a continuous function with as |x| → ∞ then show that every line y = mx intersects the curve .
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IIT 1991 |
|
1302 |
Let f : ℝ → ℝ be any function. Define g : ℝ → ℝ by g (x) = |f (x)| for all x. Then g is a) Onto if f is onto b) One to one if f is one to one c) Continuous if f is continuous d) Differentiable if f is differentiable
Let f : ℝ → ℝ be any function. Define g : ℝ → ℝ by g (x) = |f (x)| for all x. Then g is a) Onto if f is onto b) One to one if f is one to one c) Continuous if f is continuous d) Differentiable if f is differentiable
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IIT 2000 |
|
1303 |
Evaluate a) b) c) d)
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IIT 1993 |
|
1304 |
Let f : ℝ → ℝ be a function defined by f (x) = . The set of points where f (x) is not differentiable is a) } b) c) {0, 1} d)
Let f : ℝ → ℝ be a function defined by f (x) = . The set of points where f (x) is not differentiable is a) } b) c) {0, 1} d)
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IIT 2001 |
|
1305 |
If f is a differentiable function satisfying for all n ≥ 1, n I then a) b) c) d) is not necessarily zero
If f is a differentiable function satisfying for all n ≥ 1, n I then a) b) c) d) is not necessarily zero
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IIT 2005 |
|
1306 |
Evaluate
Evaluate
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IIT 2005 |
|
1307 |
Multiple choices The function f (x) = 1 + |sinx| is a) continuous nowhere b) continuous everywhere c) differentiable nowhere d) not differentiable at x = 0 e) not differentiable at infinite number of points
Multiple choices The function f (x) = 1 + |sinx| is a) continuous nowhere b) continuous everywhere c) differentiable nowhere d) not differentiable at x = 0 e) not differentiable at infinite number of points
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IIT 1986 |
|
1308 |
Let f (x) be continuous and g (x) be a discontinuous function. Prove that f (x) + g (x) is a discontinuous function. a) True b) False c) Could be continuous or discontinuous
Let f (x) be continuous and g (x) be a discontinuous function. Prove that f (x) + g (x) is a discontinuous function. a) True b) False c) Could be continuous or discontinuous
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IIT 1987 |
|
1309 |
Draw the graph of the function y = [x] + |1 – x|, – 1 ≤ x ≤ 3. Determine the points, if any, where the function is not differentiable. a) y is differentiable everywhere b) y is not differentiable at x = 0 c) y is not differentiable at x = 0, 1, 2 d) y is not differentiable at x = 0, 1, 2 and 3
Draw the graph of the function y = [x] + |1 – x|, – 1 ≤ x ≤ 3. Determine the points, if any, where the function is not differentiable. a) y is differentiable everywhere b) y is not differentiable at x = 0 c) y is not differentiable at x = 0, 1, 2 d) y is not differentiable at x = 0, 1, 2 and 3
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IIT 1989 |
|
1310 |
In how many ways can a pack of 52 cards be divided in 4 sets, three of them having 17 cards each and fourth just one card.
In how many ways can a pack of 52 cards be divided in 4 sets, three of them having 17 cards each and fourth just one card.
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IIT 1979 |
|
1311 |
Let f(x), x ≥ 0 be a non-negative function and let F(x) = . For some c > 0, f(x) ≤ cF(x) for all x ≥ 0. Then for all x ≥ 0, f(x) = a) 0 b) 1 c) 2 d) 4
Let f(x), x ≥ 0 be a non-negative function and let F(x) = . For some c > 0, f(x) ≤ cF(x) for all x ≥ 0. Then for all x ≥ 0, f(x) = a) 0 b) 1 c) 2 d) 4
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IIT 2001 |
|
1312 |
In a certain test students gave wrong answers to at least i questions where i = 1, 2, …, k. No student gave more than k correct answers. Total number of wrong answers given is . . .
In a certain test students gave wrong answers to at least i questions where i = 1, 2, …, k. No student gave more than k correct answers. Total number of wrong answers given is . . .
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IIT 1982 |
|
1313 |
If arg(z) < 0 then arg(−z) – arg(z) is equal to a) π b) –π c) – π/2 d) π/2
If arg(z) < 0 then arg(−z) – arg(z) is equal to a) π b) –π c) – π/2 d) π/2
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IIT 2000 |
|
1314 |
If ω(≠1) be a cube root of unity and then the least positive value of n is a) 2 b) 3 c) 5 d) 6
If ω(≠1) be a cube root of unity and then the least positive value of n is a) 2 b) 3 c) 5 d) 6
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IIT 2004 |
|
1315 |
If A = , 6A-1 = A2 + cA + dI then (c, d ) is a) (−11, 6) b) (−6, 11) c) (6, 11 ) d) (11, 6 )
If A = , 6A-1 = A2 + cA + dI then (c, d ) is a) (−11, 6) b) (−6, 11) c) (6, 11 ) d) (11, 6 )
|
IIT 2005 |
|
1316 |
Prove that
Prove that
|
IIT 1997 |
|
1317 |
The function f(x) = |px – q|+ r|x|, x when p > 0, q > 0, r > 0 assumes minimum value only on one point if a) p ≠ q b) r ≠ q c) r ≠ p d) p = q = r
The function f(x) = |px – q|+ r|x|, x when p > 0, q > 0, r > 0 assumes minimum value only on one point if a) p ≠ q b) r ≠ q c) r ≠ p d) p = q = r
|
IIT 1995 |
|
1318 |
Let f(θ) = sinθ (sinθ + sin3θ) then f(θ) a) ≥ 0 only when θ ≥ 0 b) ≤ 0 for all real θ c) ≥ 0 for all real θ d) ≤ θ only when θ ≤ 0
Let f(θ) = sinθ (sinθ + sin3θ) then f(θ) a) ≥ 0 only when θ ≥ 0 b) ≤ 0 for all real θ c) ≥ 0 for all real θ d) ≤ θ only when θ ≤ 0
|
IIT 2000 |
|
1319 |
Let y = f(x) is a cubic polynomial having maximum at x = − 1 and has a minimum at x = 1 and f(−1) = 10, f(1) = − 6. Find the cubic polynomial and also find the distance between the points which are maxima or minima. a) b) c) d)
Let y = f(x) is a cubic polynomial having maximum at x = − 1 and has a minimum at x = 1 and f(−1) = 10, f(1) = − 6. Find the cubic polynomial and also find the distance between the points which are maxima or minima. a) b) c) d)
|
IIT 2005 |
|
1320 |
The domain of definition of the function is a) b) c) d)
The domain of definition of the function is a) b) c) d)
|
IIT 2002 |
|
1321 |
The set of values of x which ln(1 + x) ≤ x is equal to . . . . a) (−∞, −1) b) (−1, 0) c) (0, 1) d) (1, ∞)
The set of values of x which ln(1 + x) ≤ x is equal to . . . . a) (−∞, −1) b) (−1, 0) c) (0, 1) d) (1, ∞)
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IIT 1987 |
|
1322 |
If, then g(f(x)) is invertible in the domain a) b) c) d)
If, then g(f(x)) is invertible in the domain a) b) c) d)
|
IIT 2004 |
|
1323 |
Evaluate a) b) c) d)
|
IIT 2006 |
|
1324 |
Show that the integral of sinxsin2xsin3x + sec2xcos22x + sin4xcos4x is
Show that the integral of sinxsin2xsin3x + sec2xcos22x + sin4xcos4x is
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IIT 1979 |
|
1325 |
= a) +c b) +c c) +c d)
|
IIT 1980 |
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