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Question 117

A circle passes through the point (a, b) and cuts the circle x2 + y2 = p2 orthogonally then the equation of the locus of its centre is


a) 2ax + 2by – (a2 + b2 + p2) = 0

b) x2 + y2 – 2ax – 3by + (a2 – b2 – p2) = 0

c) 2ax + 2by – (a2 – b2 + p2) = 0

d) x2 + y2 – 3ax – 4by + (a2 + b2 – p2) = 0

AIEEE 2005

Your Answer

ABCD   CLEAR